# Python program to find reverse of a number

Hello everyone, welcome back! Here we will learn a simple python logic to reverse a number.

Here we read a number from the user and reverse that number using some arithmetic operations like mod (%) and floor division (//) to find each digit and build the reverse of it.
We can also do this in an efficient way by using slice operations, reversing a number using slice is discussed in the previous post.

You can also watch the video on YouTube here

#### Reverse a number – Code Visualization

To reverse a given integer number.

#### Approach :

1. Read an input number using `input()` or `raw_input()`.
2. Check whether the value entered is integer or not.
3. Check integer is greater than 0
4. Initialise a variable named `reverse` to 0
5. Find `remainder` of the input number by using mod (%) operator
6. Now multiply `reverse` with 10 and add `remainder` to it
7. Floor Divide input number with 10
8. At some point input number will become 0
9. Repeat steps 5, 6, 7 until input number is not greater than zero
10. Print the variable `reverse`.

#### Program :

```input_num = (input("Enter any Number: "))
reverse = 0
try:
val = int(input_num)
while val > 0:
reminder = val % 10
reverse = (reverse * 10) + reminder
val //= 10
print('Reverse of entered number is : ', reverse)
except ValueError:
print("That's not a valid number, Try Again !")```

#### Output :

##### Course Suggestion

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Course:
Object Oriented Programming in Python