Python Program to check Armstrong number or not

Hello readers, welcome back, here is another simple python program which checks whether a number is an Armstrong number or not.

Generally, a number is said to be an Armstrong number if an n -digit number equal to the sum of the nth powers of its digits.

For Example, 153 is an Armstrong number as its sum of cubes of each digit 13 + 53 + 33 = 153 whereas 456 is not as its sum of cubes of each digit is not 456.


You can watch the video on YouTube here.

Program on Github

Armstrong number – Code Visualization

Task :

Python program to check an integer number is an Armstrong number or not.

Approach :

  1. Read an input number using input() or raw_input().
  2. Check whether the value entered is an integer or not.
  3. Check input_num is greater than 0.
  4. Initialize a variable named arm_num to 0.
  5. Find remainder of the input number by using mod (%) operator to get each digit in the number.
  6. Now cube each digit and add it to arm_num.
  7. Floor Divide the number by 10.
  8. Repeat steps 5. 6. 7 until the input_num is not greater than 0.
  9. If input_num is equal to arm_num, print number is ARMSTRONG.
  10. When input_num is not equals to arm_num, the number is NOT an Armstrong number.

Program on Github

Program :

__author__ = 'Avinash'

input_num = (input("Enter any number: "))
digit_len = len(str(input_num))

    arm_num = 0
    val = int(input_num)
    while val > 0:
        reminder = val % 10
        arm_num += reminder ** digit_len
        val //= 10

    if int(input_num) == arm_num:
        print(input_num, 'is an ARMSTRONG number')
        print(input_num, 'is NOT an armstrong number')

except ValueError:
    print("That's not a valid number, Try Again !")

Output :

Armstrong number -
Armstrong number –
Armstrong number -
Armstrong number –
Armstrong number -
Armstrong number –

Program on Github

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