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Python Program to print pattern of letter S

Python Program to print pattern of letter S

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter S. In the previous tutorials, I have shown you the patterns of letters A to R. Here it’s now time for Pattern S. You can check the complete series on letter patterns here.

Program on GitHub

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Print Pattern S – Code Visualization

Task:

Python program to print the pattern of letter S

Approach:

  • Read an input integer for asking the size of the letter using input()
  • Check if the entered number is greater than 8,
    • if yes, call the function print_pattern()
    • else, show a message to enter a number that is greater or equal to 8
  • print_pattern()
    • here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern O
    • following are 5 conditions for printing *’s
      We have 2 loops, an outer loop() for rows, and an inner loop for columns

      • # Outer for loop 
        for row in range(n): 
        
            # Inner for loop 
            for column in range(n):
        • Print first row
          • row == 0 and column != 0 and column != n - 1
        • Print first column
          • column == 0 and row != 0 and row < n//2
        • Print middle row
          • row == n//2 and column != n-1 and column != 0
        • Print last column
          • column == n-1 and row > n//2 and row != n-1
        • Print last row
          • row == n-1 and column != 0 and column != n - 1
        • print ` ` in remaining all cases.

Program on GitHub

Program:

__author__ = 'Avinash'

# Python3 program to print alphabet pattern S

#   * * * * * * *
# *
# *
# *
#   * * * * * * *
#                 *
#                 *
#                 *
#   * * * * * * *


def print_pattern(n):
    for row in range(n):
        for column in range(n):
            if (
                    # first row
                    (row == 0 and column != 0 and column != n - 1) or

                    # first column
                    (column == 0 and row != 0 and row < n//2) or

                    # middle row
                    (row == n//2 and column != n-1 and column != 0) or

                    # last column
                    (column == n-1 and row > n//2 and row != n-1) or

                    # last row
                    (row == n-1 and column != 0 and column != n - 1)
            ):
                print("*", end=" ")
            else:
                print(" ", end=" ")
        print()

size = int(input("Enter any size: \t"))

if size < 8:
    print("Enter a size minimum of 8")
else:
    print_pattern(size)

Output:

Python Program to print pattern of letter S
Python Program to print pattern of letter S

Program on Github

Online Python Compiler

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