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# Python Program to print pattern of Letter D Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter ‘D’. In the previous tutorials, I have shown you the pattern for the letter ‘C’, Letter A, and Letter B. Here it’s now time for Pattern D.

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Python program to print the pattern of letter ‘D’

#### Approach:

• Read an input integer for asking the size of the letter using  `input()`
• Check if the entered number is greater than 8,
• if yes, call the function `print_pattern()`
• else, show a message to enter a number that is greater or equal to 8
• print_pattern()
• here we only do two things, print star(`*`) and print space(` `), just writing conditions so the pattern of `*`‘s and ` `‘s will display the pattern ‘D’
• following are 3 conditions for printing *’s
We have 2 loops, outer loop() for rows and inner loop for columns.

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```# Outer for loop
for row in range(n):
# Inner for loop
for column in range(n - 2):```
• Print first and last row
`((row == 0 or row == n-1) and (0 < column < n-3))`
• Print first column
`column == 0`
• Print last column
`column == n - 3 and (row != 0 and row != n - 1)`
• print ` ` in remaining all cases.

#### Program:

```__author__ = 'Avinash'

# Python3 program to print alphabet pattern D
def print_pattern(n):
# Outer for loop for number of rows
for row in range(n):
# Inner for loop columns
for column in range(n - 2):
# prints first and last row
if (
((row == 0 or row == n-1) and (0 < column < n-3)) or
# prints first column
column == 0 or
# prints last column
column == n - 3 and (row != 0 and row != n - 1)
):
print("*", end=" ")
else:
print("  ", end="")
print()

# Size of the letter
num = int(input("Enter the size \t"))

if num < 8:
print("Enter a number atleast 8")
else:
print_pattern(num)
```