Hello everyone, welcome back to programminginpython.com! Here I am going to explain to you how to implement a linear search algorithm in python. This linear search is a basic search algorithm that searches all the elements in the list and finds the required value. This is also known as a sequential search.

Here in this technique, I compare each and every element with the key element to be found, if both of them match, the algorithm returns that element is found and its position.

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#### Code Visualization – Linear Search Algorithm

#### Time Complexity

Best Case |
O(1) |

Average Case |
O(n) |

Worst Case |
O(n) |

#### Algorithm

Given a list `L`

of `n` elements with values or records,`L0 ... Ln-1`

and key/target element `K`

, linear search is used to find the index/position of the target `K`

in list `L`

- Initialize a boolean variable
`found`

and set it to False initially - Start for loop with
`i`

ranging from 0 to the length of the list - Check if key element is equal to
`L[i]`

- if equals
- set
`found`

boolean variable to `True` - print the position of the element found
- break for loop

- set

- if equals
- If the boolean variable
`found`

is equal to`False`

after for loop, print that the element is not found in the list

#### Program

__author__ = 'Avinash' lst = [] num = int(input("Enter size of list: \t")) for n in range(num): numbers = int(input("Enter any number: \t")) lst.append(numbers) x = int(input("\nEnter number to search: \t")) found = False for i in range(len(lst)): if lst[i] == x: found = True print("\n%d found at position %d" % (x, i)) break if not found: print("\n%d is not in list" % x)